The Derivative of sin(3x)

The derivative of sin3x is 3cos(3x)

The derivative of sin(3x) is 3cos(3x)


How to calculate the derivative of sin(3x)

Note that in this post we will be looking at differentiating sin(3x) which is not the same as differentiating sin3(x). Here is our post dealing with how to differentiate sin3(x).

The chain rule is useful for finding the derivative of a function which could have been differentiated had it been in x, but it is in the form of another expression which could also be differentiated if it stood on its own.

In this case:

  • We know how to differentiate sin(x) (the answer is cos(x))
  • We know how to differentiate 3x (the answer is 3)

This means the chain rule will allow us to differentiate the expression sin(3x).

Using the chain rule to find the derivative of sin(3x)

To perform the differentiation sin(3x), the chain rule says we must differentiate the expression as if it were just in terms of x as long as we then multiply that result by the derivative of what the expression is actually in terms of (in this case the derivative of 3x).

Let’s call the function in the argument of sin, g(x), which means the function is in the form of sin(x), except it does not have x as the angle, instead it has another function of x (3x) as the angle.

If:

g(x) = 3x

It follows that:

sin(3x) = sin(g(x))

So if the function f(x) = sin(x) and the function g(x) = 3x, then the function sin(3x) can be written as a composite function.

f(x) = sin(x)

f(g(x)) = sin(g(x)) (but g(x) = 3x))

f(g(x)) = sin(3x)

Let’s define this composite function as F(x):

F(x) = f(g(x)) = sin(3x)

We can find the derivative of sin(3x) (F'(x)) by making use of the chain rule.


The Chain Rule:
For two differentiable functions f(x) and g(x)


If F(x) = f(g(x))


Then the derivative of F(x) is F'(x) = f’(g(x)).g’(x)


Now we can just plug f(x) and g(x) into the chain rule. But before we do that, just a quick recap on the derivative of the sin function.

The derivative of sin(x) with respect to x is cos(x)
The derivative of sin(z) with respect to z is cos(z)

In a similar way, the derivative of sin(3x) with respect to 3x is cos(3x).

We will use this fact as part of the chain rule to find the derivative of sin(3x) with respect to x.

How to find the derivative of sin(3x) using the Chain Rule:

F'(x)= f'(g(x)).g'(x)Chain Rule Definition
= f'(g(x))(3)g(x) = 3x ⇒ g'(x) = 3
= (cos(3x)).(3)f(g(x)) = sin(3x) f'(g(x)) = cos(3x)
= 3cos(3x)

Using the chain rule, the derivative of sin(3x) is 3cos(3x)


Finally, just a note on syntax and notation: sin(3x) is sometimes written in the forms below (with the derivative as per the calculation above). Just be aware that not all of the forms below are mathematically correct.

sin3x► Derivative of sin3x = 3cos(3x)
sin3x► Derivative of sin3x = 3cos(3x)
sin 3x► Derivative of sin 3x = 3cos(3x)
sin (3x)► Derivative of sin (3x) = 3cos(3x)

The Second Derivative Of sin(3x)

To calculate the second derivative of a function, you just differentiate the first derivative.

From above, we found that the first derivative of sin(3x) = 3cos(3x). So to find the second derivative of sin(3x), we just need to differentiate 3cos(3x)

We can use the chain rule to find the derivative of 3cos(3x) and it gives us a result of -9sin(3x)

The second derivative of sin(3x) is -9sin(3x)

The Derivative of ln(8x)

The derivative of ln(8x) is 1/x

The derivative of ln(8x) is 1/x


How to calculate the derivative of ln(8x)

There are two methods that can be used for calculating the derivative of ln(8x).

The first method is by using the chain rule for derivatives.

The second method is by using the properties of logs to write ln(8x) into a form which differentiable without needing to use the chain rule.

Finding the derivative of ln(8x) using the chain rule

The chain rule is useful for finding the derivative of an expression which could have been differentiated had it been in x, but it is in the form of another expression which could also be differentiated if it stood on its own.

In this case:

  • We know how to differentiate 8x (the answer is 8)
  • We know how to differentiate ln(x) (the answer is 1/x)

This means the chain rule will allow us to perform the differentiation of the function ln(8x).

To perform the differentiation, the chain rule says we must differentiate the expression as if it were just in terms of x as long as we then multiply that result by the derivative of what the expression was actually in terms of (in this case the derivative of 8x).

Using the chain rule to find the derivative of ln(8x)

ln(8x) is in the form of the standard natural log function ln(x), except it does not have x as an argument, instead it has another function of x (8x).

Let’s call the function in the argument g(x), which means:

g(x) = 8x

From this it follows that:

ln(8x) = ln(g(x))

So if the function f(x) = ln(x) and the function g(x) = 8x, then the function ln(8x) can be written as a composite function.

f(x) = ln(x)

f(g(x)) = ln(g(x)) (but g(x) = 8x)

f(g(x)) = ln(8x)

Let’s define this composite function as F(x):

F(x) = f(g(x)) = ln(8x)

We can find the derivative of ln(8x) (F'(x)) by making use of the chain rule.


The Chain Rule:
For two differentiable functions f(x) and g(x)

If F(x) = f(g(x))


Then the derivative of F(x) is F'(x) = f’(g(x)).g’(x)


Now we can just plug f(x) and g(x) into the chain rule.

Now we can just plug f(x) and g(x) into the chain rule. But before we do that, just a quick recap on the derivative of the natural logarithm.

The derivative of ln(x) with respect to x is (1/x)
The derivative of ln(s) with respect to s is (1/s)

In a similar way, the derivative of ln(8x) with respect to 8x is (1/8x).
We will use this fact as part of the chain rule to find the derivative of ln(8x) with respect to x.

How to find the derivative of ln(8x) using the Chain Rule:

F'(x)= f'(g(x)).g'(x)Chain Rule Definition
= f'(g(x)).(8)g(x) = 8x ⇒ g'(x) = 8
= (1/8x).8f(g(x)) = ln(8x) ⇒ f'(g(x)) = 1/8x
(The derivative of ln(8x) with respect to 8x is (1/8x))
= 1/x

Using the chain rule, we find that the derivative of ln(8x) is 1/x


Finally, just a note on syntax and notation: ln(8x) is sometimes written in the forms below (with the derivative as per the calculations above). Just be aware that not all of the forms below are mathematically correct.

ln8x► Derivative of ln8x =1/x
ln 8x► Derivative of ln 8x = 1/x
ln 8 x► Derivative of ln 8 x = 1/x

Top Tip

It’s possible to generalize the derivative of expressions in the form ln(ax) (where a is a constant value):

The derivative of ln(ax) = 1/x


(Regardless of the value of the constant, the derivative of ln(ax) is always 1/x)


Finding the derivative of ln(8x) using log properties

Since ln is the natural logarithm, the usual properties of logs apply.

The product property of logs states that ln(xy) = ln(x) + ln(y). In other words taking the log of a product is equal to the summing the logs of each term of the product.

Since 8x is the product of 8 and x, we can use the product properties of logs to rewrite ln(8x):

f(x) = ln(8x) = ln(8) + ln(x)

How to find the derivative of ln(8x) using the product property of logs

f(x)= ln(8) + ln(x)
f'(x)= 0 + ln(x)ln8 is a constant, the derivative of a constant is 0
= 0 + 1/xThe derivative of ln(x) is 1/x
= 1/x

The Second Derivative of ln(8x)

To calculate the second derivative of a function, you just differentiate the first derivative.

From above, we found that the first derivative of ln(8x) = 1/x. So to find the second derivative of ln(8x), we just need to differentiate 1/x

If we differentiate 1/x we get an answer of (-1/x2).

The second derivative of ln(8x) = -1/x2

The Derivative of tan(2x)

The derivative of tan2x is 2sec^2(2x)

The derivative of tan(2x) is 2sec2(2x)


How to calculate the derivative of tan(2x)

Note that in this post we will be looking at differentiating tan(2x) which is not the same as differentiating tan2(x). Here is our post dealing with how to differentiate tan^2(x).

The chain rule is useful for finding the derivative of a function which could have been differentiated had it been in x, but it is in the form of another expression which could also be differentiated if it stood on its own.

In this case:

  • We know how to differentiate tan(x) (the answer is sec2(x))
  • We know how to differentiate 2x (the answer is 2)

This means the chain rule will allow us to differentiate the expression tan(2x).

Using the chain rule to find the derivative of tan(2x)

To perform the differentiation tan(2x), the chain rule says we must differentiate the expression as if it were just in terms of x as long as we then multiply that result by the derivative of what the expression is actually in terms of (in this case the derivative of 2x).

Let’s call the function in the argument of tan, g(x), which means the function is in the form of tan(x), except it does not have x as the angle, instead it has another function of x (2x) as the angle

If:

g(x) = 2x

It follows that:

tan(2x) = tan(g(x))

So if the function f(x) = tan(x) and the function g(x) = 2x, then the function tan(2x) can be written as a composite function.

f(x) = tan(x)

f(g(x)) = tan(g(x)) (but g(x) = 2x))

f(g(x)) = tan(2x)

Let’s define this composite function as F(x):

F(x) = f(g(x)) = tan(2x)

We can find the derivative of tan(2x) (F'(x)) by making use of the chain rule.


The Chain Rule:
For two differentiable functions f(x) and g(x)


If F(x) = f(g(x))


Then the derivative of F(x) is F'(x) = f’(g(x)).g’(x)


Now we can just plug f(x) and g(x) into the chain rule. But before we do that, just a quick recap on the derivative of the tan function.

The derivative of tan(x) with respect to x is sec2(x)
The derivative of tan(z) with respect to z is sec2(z)

In a similar way, the derivative of tan(2x) with respect to 2x is sec2(2x).

We will use this fact as part of the chain rule to find the derivative of tan(2x) with respect to x.

How to find the derivative of tan(2x) using the Chain Rule:

F'(x)= f'(g(x)).g'(x)Chain Rule Definition
= f'(g(x))(2)g(x) = 2x ⇒ g'(x) = 2
= (sec2(2x)).(2)f(g(x)) = tan(2x) f'(g(x)) = sec2(2x)
= 2sec2(2x)

Using the chain rule, the derivative of tan(2x) is 2sec2(2x)


Finally, just a note on syntax and notation: tan(2x) is sometimes written in the forms below (with the derivative as per the calculation above). Just be aware that not all of the forms below are mathematically correct.

tan2x► Derivative of tan2x = 2sec2(2x)
tan 2 x► Derivative of tan 2 x = 2sec2(2x)
tan 2x► Derivative of tan 2x = 2sec2(2x)
tan (2x)► Derivative of tan (2x) = 2sec2(2x)

The Second Derivative Of tan(2x)

To calculate the second derivative of a function, you just differentiate the first derivative.

From above, we found that the first derivative of tan(2x) = 2sec2(2x). So to find the second derivative of tan(2x), we just need to differentiate 2sec2(2x).

We can use the chain rule to find the derivative of 2sec2(2x) (bearing in mind that the derivative of sec^2(x) is 2sec2(x)tan(x)) and it gives us a result of 8sec2(2x)tan(2x)

The second derivative of tan(2x) is 8sec2(2x)tan(2x)